-25x^2+169=0

Solution for -25x^2+169=0 equation:

-25x^2+169=0

a = -25; b = 0; c = +169;
Δ = b2-4ac
Δ = 02-4·(-25)·169
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-130}{2*-25}=\frac{-130}{-50}
=2+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+130}{2*-25}=\frac{130}{-50}
=-2+3/5
$